# -*- coding: utf-8 -*-
"""loops.ipynb

Automatically generated by Colaboratory.

Original file is located at
    https://colab.research.google.com/drive/1I-Okj_eE9P9GHPo3xJdO7eYHsFa7Kqs1

# If, Elif a Else
"""

x = int(input('Type number: '))

x = 2
if x > 6 == 0:
    print(x, 'je vic')
if x == 5:
    print('pet')
elif x < 6:
        print(x, 'je mene')
else:
    print("A to je dobre.")

if 4 in [4, 5, 6]:
    print('je tam')

"""# Range"""

list(range(10))

list(range(0, 10, 2))

"""# For"""

for i in range(3):
    print(i)

for letter in 'python':
    if letter == 'p':
        print('')
    else:
        print(letter)

for i, letter in enumerate('python'):
    print(i, 'ty letter je ', letter)

for letter in 'python':
    if letter == 'p':
        break
    else:
        print(letter)
    print('end loop')

x = 1
while x > 0:
    x += 1
    print(x)

"""# List comprehension"""

list_comprehen="""numbers =[0, 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4]
odd_numbers = [x for x in numbers if x % 2 == 1] # {x| x nalezi numbers a ma zbytek 1 po deleni 2}
"""

import timeit

timeit.timeit(list_comprehen)

classic="""numbers = [0, 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4]
odd_numbers_long = []

for x in numbers:
    if x % 2 == 1:
        odd_numbers_long.append(x)"""

timeit.timeit(classic)

our_dict = {x: x>2 for x in numbers}

"""NEPOUZIVAT KLICOVA SLOVA PYTHONU JAKO PROMENE JINAK SE Z TOHO ZBLAZNITE viz str !"""

str(3)

str

{x: "Ano" for x in our_dict.values()}

{y: x for x, y in our_dict.items()}

[x for x in our_dict.items()]

for x in our_dict.values:
    print(x)
## POZOR values, items, keys ap. jsou slovnikove METODY a tedy je treba je zavolat, konci ()